11y^2-98y-120=0

Solution for 11y^2-98y-120=0 equation:

11y^2-98y-120=0

a = 11; b = -98; c = -120;
Δ = b2-4ac
Δ = -982-4·11·(-120)
Δ = 14884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14884}=122$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-122}{2*11}=\frac{-24}{22}
=-1+1/11
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+122}{2*11}=\frac{220}{22}
=10
$